(4n+3)(2n^2-3n+1)=

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Solution for (4n+3)(2n^2-3n+1)= equation:


Simplifying
(4n + 3)(2n2 + -3n + 1) = 0

Reorder the terms:
(3 + 4n)(2n2 + -3n + 1) = 0

Reorder the terms:
(3 + 4n)(1 + -3n + 2n2) = 0

Multiply (3 + 4n) * (1 + -3n + 2n2)
(3(1 + -3n + 2n2) + 4n * (1 + -3n + 2n2)) = 0
((1 * 3 + -3n * 3 + 2n2 * 3) + 4n * (1 + -3n + 2n2)) = 0
((3 + -9n + 6n2) + 4n * (1 + -3n + 2n2)) = 0
(3 + -9n + 6n2 + (1 * 4n + -3n * 4n + 2n2 * 4n)) = 0
(3 + -9n + 6n2 + (4n + -12n2 + 8n3)) = 0

Reorder the terms:
(3 + -9n + 4n + 6n2 + -12n2 + 8n3) = 0

Combine like terms: -9n + 4n = -5n
(3 + -5n + 6n2 + -12n2 + 8n3) = 0

Combine like terms: 6n2 + -12n2 = -6n2
(3 + -5n + -6n2 + 8n3) = 0

Solving
3 + -5n + -6n2 + 8n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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